Recent comments in /f/technology

jepvr t1_j9pl5uh wrote

I love that the excuse is that it informs the person that this isn't the person it's imitating and is actually a computer. Then... why even imitate the voice? You're making it worse than just saying "______ isn't able to answer, but this is her assistant Bixby and" etc. That gives you the same functionality but is so much less of a WTF.

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baddfingerz1968 t1_j9pk4nd wrote

I am one of them too, really, just for myself. But in this insane Age of Trump I have gotten a lot more conscious and everyday am looking at the big picture to see what I can contribute, what I can do to fight the future.

In reality, it is little, but even just being a social justice warrior is something. I think just always staying conscious and aware, and maintaining the right attitude and state of mind is paramount.

And simply connecting with others like right now.

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friedAmobo t1_j9pjslw wrote

It's possible, though flipping through iFixit's guides (the 2G, 3G, 3GS, 4, 5, 6, 7, 11, and 14 models), the first time adhesive pull tabs were referenced by them was in the iPhone 3G (the second-generation iPhone). They recommended against using the pull tabs in the 3G and 3GS, though. Unless Apple removed the pull tab at some point and then added it back in soon after (between the model generations I checked), it seems like iPhones have consistently had some form of a pull tab after the original iPhone.

What might have been possible is that the adhesive may have aged to the point where the pull tabs were no longer usable in your iPhone when you repaired it and the battery was essentially glued/adhered to the chassis at that point. Without the pull tabs (which can break when trying to use them), the battery adhesive basically becomes the same as the display adhesive, which also requires heat to remove.

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GhostRid3r16 t1_j9pj6hp wrote

> Because of this knowing where a particle is how fast its moving or its spin direction isnt possible.

No, that’s due to wave/particle duality leading to the uncertainty principle. There’s uncertainty in where a quantum particle exists or goes thanks to the fact that all of our measurement tools are too big and waves don’t exist at a point. Consider using a meter stick to measure the width of a piece of paper. You will have an uncertainty wave packet width of 1mm at best. That is a better analogy for uncertainty. The paper is the electron and the meter stick is the observation/measurement, where instead of 1mm it’s h/4π meter.

> And measuring one property effects the particle so the others cant be measured.

Also not true, and a common lay misinterpretation (by those who haven’t been instructed on quantum I mean). You can measure Px with certainty but not simultaneously X. You can meaaure Py with certainty but not simultaneously y. Likewise Pz and not z. You can however simultaneously measure Px without affecting the state or certainty of y,z or Py, Pz. And so on for [Py,x]=0, [Pz,y]=0 etc.

It’s only σPxσx = σPyσy = σPzσz = σEσt >= h/4π; where σPxσy = σPyσX etc = 0 believe it or not. The uncertainties are coupled to the vectors. If you want you can find absolute certainty in X momentum and y position without collapsing the wave function for Pz,z. Absolute certainty for the complete vector components or the particle as a whole is not possible.

Mathematically that looks like this: https://i.imgur.com/XbCrYh3.jpg : expectation of Δx^2 • expectation of Δp(x)^2 = h^(2)/16π^2 where <Δx^(2)> = <x^(2)> - <x>^2 , same for <Δp(x)^(2)>. For quantum systems; Scale up and these uncertainties become so small as to be negligible to the system, and we’re back in Newtonian kinematics (correspondence principle).

Let’s also take note that the form is of ΔxΔPx>=h/4π: so this means, you can measure x with certainty much higher than h/4π; for instance let’s say you measure x to a certainty of h/10^(5)π. ΔPx must therefore be required to have an uncertainty that satisfies ΔxΔPx>=h/4π where ΔPx >= h/4πΔx, or ΔPx >= h/4πh/10^(5)π >= 10^(5)/4, and that’s in kgm/s. So our uncertainty in momentum rises to 25,000 kgm/s for a certainty in position of h/10^(5)π.

It’s plain to see here that as Δx goes to zero as we would approach absolute certainty, ΔPx must go to infinity, and to absolute uncertainty. You can know exactly where a particle was and know nothing about where it will be, or you can know exactly where a particle is going and know nothing about where it was. And keep in mind without both of those you can’t model the motion. Enter the wave interpretation of quantum systems, aka Quantum Mechanics, a(less)ka Wave Mechanics, and statistical analysis of the wave function provides us a model of behavior before and after measurement within the parameters of ΔrΔPr>=h/4π.. where you actually don’t need both parameters of initial position and momentum to model the wave function through time as it’s only a first derivative with respect to time!! YAY! And rejoice because if it was δ^(2)/δt^2 we’d all be fucked and stuck only with experimental data and no closed form solutions.

As a side note about entanglement: consider what I’ve said about measurements collapsing the wave function: let’s say you have 2 electrons and they interact. That is, they bounce into each other and are deflected. We know from Newtonian mechanics that if we solve the current position and momentum of one particle, we can wind back time and reconstruct the collision. The consequence of this in quantum means that when you measure the physical properties of one of the entangled particles, you necessarily have measured the properties of the other particle. This collapses both waveforms, since you have gained knowledge of the system of particles through measurement. You can reconstruct b from a. Therefore you have collapsed b’s waveform as well when you measure and collapse a’s. And thus, the particles are said to be entangled at the quantum level, the same way a cue ball is paired to an 8 ball at the Newtonian level. Measuring the properties of the 8 ball necessarily tells you the properties of the cue ball.

Also interesting aside: black holes produce a pair of electrons at the event horizon boundary, where at a certain probability, one of the electrons has been pulled into the black hole, and the other released into the universe so to speak. For one instant in time, this is the ONLY truly unpaired particle in the universe.

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zabuu t1_j9piwn2 wrote

Not quite... once you observe (read: measure) an entangled particle, it is no longer entangled.

Imagine 2 people face to face on a perfectly slippery frozen lake. If they push apart from each other, they would slide away. If you know the mass of each person, and you catch person A (this is like measuring the speed), then you'll know how fast person B is going. But measuring A changed the system and you'll get no additional info about B.

I'm no pro though, this is just how I understand it.

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SeanHaz t1_j9phsxg wrote

If you increase the cost we can't afford it, if you keep the cost the way it is we'll have the same problems.

I'm not saying it should be ruled out because it's not perfect, I think it should be ruled out because it is worse than your current system.

It has "worked" in Ireland for decades, it has also"worked" in the US for decades...to me it isn't obvious the public system is better. I know the USA had the most ventilators compared to its population which helped save a lot of lives during COVID, it's more expensive but you get what you pay for.

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boldberserker t1_j9pf6rg wrote

I’m not saying it would be perfect or easy. Many people die in the US because they can’t afford healthcare even if they have insurance. It sounds like changes to the payment model for doctors and nurses need to be made in Ireland and the UK. It shouldn’t take years in a bureaucratic process to make those changes. Just because something isn’t perfect doesn’t mean it should be ruled out. There’s ways to improve it and implement better with the advantage of seeing how it has worked elsewhere for decades.

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